the fractions 42/491, 30/313 and 35/367 are arranged in ascending order of magnitude as
Answers
Answer:
42/491 , 35/367 , 30/313
Step-by-step explanation:
The fractions 42/491, 30/313 and 35/367 are arranged in ascending order of magnitude as
42/491 30/313 35/367
Lets make denominator of all numbers common
42/491 = 42 * 313 * 367 / (491 * 313 * 367) = 4824582 / (491 * 313 * 367)
30/313 = 30 * 491 * 367 / (491 * 313 * 367) = 5405910 / (491 * 313 * 367)
35/367 = 35 * 313 * 491 / (491 * 313 * 367) = 5378905 / (491 * 313 * 367)
4824582 < 5378905 < 5405910
42/491 < 35/367 < 30/313
Ascending order
42/491 , 35/367 , 30/313
Other way to solve
42/491, 30/313 and 35/367
if 1/a > 1/b > 1/c
=> a < b < c
lets take reciprocal of each number
491/42 , 313/30 , 367/35
491 * 5/ 210 , 313*7/210 , 367*6/210
2455 , 2191 , 2202
2455 > 2202 > 2191
491/42 > 367/35 > 313/30
=> 42/491 < 35/367 < 30/313
Hence in ascending order
42/491 , 35/367 , 30/313