Physics, asked by rajatdimoriya1, 10 months ago

The freezing point depression constant (Kf) of
benzene is 5.12 K kg mol-1. The freezing point
depression for the solution of molality 0.078 m
containing a non-electrolyte solute in benzene is
(rounded off upto two decimal places):​

Answers

Answered by tharaniramesh2211
6

Answer:

0.40k is the answer to the question

Attachments:
Answered by nirman95
7

Given:

The freezing point depression constant (Kf) of benzene is 5.12 K kg mol-1. molality containing a non-electrolyte solute is 0.078 m.

To find:

Depression in freezing point.

Calculation:

General expression for depression in freezing point in solutions is :

 \boxed{ \rm{\Delta T =  i  \times K_{f} \times m}}

For a non-electrolyte solute , the Van't Hoff Factor will be one (1).

Now , putting available values:

 =  > \rm{\Delta T =  1  \times K_{f} \times m}

 =  > \rm{\Delta T =  1  \times 5.12 \times 0.078}

 =  > \rm{\Delta T =  0.399}

 =  > \rm{\Delta T  \approx  0.4}

So, the depression in freezing point will be :

 \boxed{\bf{\Delta T  \approx  0.4 \: K }}

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