Question

The freezing point depression of 0.001 torr Kx[Fe(CH]e] is 7.10 x 10 K. Determine the
value of x. Given K = 1.86 K kg/mol and for water.​

Answer 1

Answer:

I think 132.06 is answer

Answer 2

∆T = i×k×m

7.10×10^-3 = i×1.86×0.001

i = (7.10×10^-3)/(1.86×0.001)

i = 3.817

Now, a = (i-1)/(n-1)

=> 1 = (3.817-1)/(x+1-1)

=> x = 2.817

Thus, the value of x is: x = 2.817 ≈ 3.