Question

The freezing point depression of 0.1 molal solution
of acetic acid in benzene is 0.25 K. K for benzene
is 5.12 K kg mol-'. What conclusion can you draw
about the molecular state of acetic acid in benzene?
.​

Answer 1

Explanation:

∆Tf = K × m × i

0.25 = 5.12 × 0.1 × I

i = 2.5 / 5.12

which is approximately 0.5

hence, we can say that acetic acid associates in benzene.

for any queries, can ask in comments !