The freezing point (in °C) of solution containing 0.18 g of glucose in 100 g water is (Kf = 1.86 K kg mol–1) is
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Given
= Mass of glucose = 0.18 g
= Mass of solvent = 100 g
= Molal freezing point of water = 1.86 K kg/mol
To find
Freezing point of solution
Solution
M = Molar mass of glucose = 180.156 g/mol
Number of moles of glucose
Molality is given by
Depression in the freezing point of the solution
Freezing point of water =
Freezing point of the solution is .
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