The freezing point of 1 molal CaCl solution is -3.62°C. If kf of water is 1.86 C/m. The percentage of ionisation of CaCl, is
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Depression in freezing point of a solvent upon aaddition of solute is given as:
ΔT
f
=m.K
f
m=molality of the solution=0.0711 kg/mol
K
f
=cryoscopic constant=1.86 K kg/mol
ΔT
f
=0.0711×1.86=0.132 K
thus freezing point of water is
T
solvent
=273−0.132=272.868K=−0.132
0
C
observed ΔT
f
=−0.320
0
C
vant hoff factor, i=observed freezing point/calculated freezing point
∴ i=0.32/0.132=2.42
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