Question

The freezing point of a 10% aqueous solution by weight of x is same as freezing point of another 20% aqueous solution by weight of y,if molar mass of y is 80 molar mass of x is

Answer 1

Molar mass of X IS 40 kg/mol

Answer 2

Explanation:

35.5

1. FP of 10%aq solution = FP of 20%aq solution
2. so Kf of both solutions are equal..if they are non electrolytic solutions then I value is 1 if not multiply i value in substitution

• ∆Tf = Kf×molarity×i
• ∆Tfa=∆Tfb
• Ma= Mb
• 10/x*1000/90=20/80*1000/80
• 50/9x=10/64
• 5*64/9=x
• 35.5=x