Question

The freezing point of an aqueous solution of a non-electrolute
is -0.14 C. The molarity of this solution is [Kf (H20) = 1.86
K kg mol'] :
[B] 1.00 m
[D/0.075 m
(A) 1.86 m
[C] 0.15 m​

Answer 1

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As we know,

Vant Half factor = 1 (Non-Electrolyte)

∆Tf = kf m

m=0.14/1.86. = 0.075 m

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