The freezing point of equimolal aqueous solution will be
highest for
(a) C₆H₅NH₃ ⁺Cl⁻ (b) Ca(NO₃)₂
(c) La(NO₃)₂ (d) C₆H₁₂O₆
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The freezing point of equimolal aqueous solution will be highest for (b) Ca(NO₃)₂
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The freezing point of equimolal aqueous solution will be highest for
D) C₆H₁₂O₆.
C₆H₅NH₃ ⁺Cl⁻ ---------> C₆H₅NH₃⁺ + Cl⁻
Ca(NO₃)₂ ---------> (Ca)^2+ + 2(NO₃)^-1
La(NO₃)₂ --------> (La)^2+ + 2(NO₃)^-1
The Glucose molecule does not dissociate. It has the minimum number of particles . It's can't Hoff factor will be the least(i = 1) amongst the given molecules .
Due to this glucose has the minimum depression in freezing point and thus has the highest freezing point.
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