Question

the freezing point of normal human blood is -0. 58°C . calculate the osmotic pressure of the blood, density of blood is 1kg/dm-3​

Answer 1

Explanation:

The osmotic pressure is given by Π=CRT

Here, C is the molar concentration, R is the ideal gas constant (0.08206 L atm / mol . K) and T is the absolute temperature.

Now,

7.65=C×0.08206×(273+37)

∴C=0.3 M

⇒1 L of the solution will contain 0.3 moles of glucose. The molar mass of glucose is 180 g/mol.

This corresponds to 0.3×180=54.0 g of glucose.