Question

the freezing point on a thermometer is marked as 200 and the boiling point as 150 degree a tempreature of 60 dgree c on this thermometer will be read as​

Answer 1

Answer:

Given: Freezing point on thermometer =20 , Boiling point on thermometer =150 ,

Hence, number of equal parts on thermometer =150−20=130, temperature on celsius scale =20

o

C

Let temperature on thermometer =t ,

Therefore ,

130

t−20

=

100

60−0

,

⇒ t−20=78

⇒ t=78+20=98

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