Question

the freezing point on a thermometer is marked on 5 and boiling point on 95a temperature of 60 on this thermometer wii read as
(A) 40°. (b) 65° (c) 98° (D) 110°​

Answer 1

Correct option is

C

98

o

Given: Freezing point on thermometer =20 , Boiling point on thermometer =150 ,

Hence, number of equal parts on thermometer =150−20=130, temperature on celsius scale =20

o

C

Let temperature on thermometer =t ,

Therefore ,

130

t−20

=

100

60−0

,

⇒ t−20=78

⇒ t=78+20=98

o