The French physicist de Broglie in 1924 proposed that matter like radiation should also exhibit dual behaviour i.e. both particle and wavelike properties.This means that just as the photon has momentum as well as wavelength electrons should also have momentum as well as wavelength de Broglie from this analogy gave the following relation between wavelength (lambda) and momentum (p) of a material particle.
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Answer:
λ e>λ p >λ n
Explanation:
KE= 1/2 mv^2
⇒v= rootof 2KE/m
⇒mv= rootof 2mKE
λ= h/mv= h/ rootof 2mKE
⇒λ∝ 1/ root m
Therefore, for constant KE
∴λ e>λ p >λ n
Since electron has negligible mass.
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The French physicist de Broglie in 1924 proposed that matter like radiation should also exhibit dual behaviour i.e. both particle and wavelike properties.This means that just as the photon has momentum as well as wavelength electrons should also have momentum as well as wavelength de Broglie from this analogy gave the .......
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