Question

The frequencies of X-rays, ????-rays and ultraviolet
rays are respectively a, b, and c. Then
(a) a < b, b < c (b) a < b, b > c
(c) a > b, b > c (d) a > b, b < c

Answer 1

Explanation:

The frequencies of X-rays, ????-rays and ultraviolet

rays are respectively a, b, and c. Then

(a) a < b, b < c✓✓

(b) a < b, b > c

(c) a > b, b > c (d) a > b, b < c

Because,

The frequency of X-rays

a=3×10^19to 1×10^16

The frequency of Gamma-rays

b=3×10^22 to 3×10^18

The frequency of visible light

c=8×10^14 to 4×10^14

So, $$b > a, b > c$$

Answer 2

Answer:

$\huge{\fbox{\fbox{\bigstar{\mathfrak{\red{Answer}}}}}}$

The frequencies of X-rays, ????-rays and ultraviolet

rays are respectively a, b, and c. Then

(a) a < b, b < c ✔(b) a < b, b > c

(c) a > b, b > c (d) a > b, b < c