The frequency of a fork is 500 Hz. Velocity of sound in air is 350 ms. The distance through which
sound travel by the time the fork makes 125 vibrations is
a) 87.5 m
b) 700 m
c) 1400 m
d) 1.75 m
Answers
Answered by
1
Answer:
The time for 125 vibrations is 125/500 =0.25
sec.
the required distance is d=350×0.25
=1.75m
Answered by
5
Answer:
a. 87.5m
Explanation:
ANSWER
f=500
T= 1/f
=1/500
T is for 1 vibration.
∴ t for 125 vibrations in T×125
t= 125 /500
d=Vt
=350×125 /500
d=87.5
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