Physics, asked by kmdkh996, 6 months ago

The frequency of a photon associated with an

energy of 3.31 eV is(given h = 6.62 x 10-34 Js)​

Answers

Answered by Anonymous
6

energy \large\rm { = hν}

\large\rm { 3.31 eV = 6.62×10^{-34} ν}

\large\rm { ν = 0.8 × 10^{15} Hz}

Answered by Anonymous
1

Answer:

{ = hν}=hν

{ = hν}=hν { 3.31 eV = 6.62×10^{-34} ν}3.31eV=6.62×10

{ = hν}=hν { 3.31 eV = 6.62×10^{-34} ν}3.31eV=6.62×10 −34

{ = hν}=hν { 3.31 eV = 6.62×10^{-34} ν}3.31eV=6.62×10 −34 ν

{ = hν}=hν { 3.31 eV = 6.62×10^{-34} ν}3.31eV=6.62×10 −34 ν { ν = 0.8 × 10^{15} Hz}ν=0.8×10

{ = hν}=hν { 3.31 eV = 6.62×10^{-34} ν}3.31eV=6.62×10 −34 ν { ν = 0.8 × 10^{15} Hz}ν=0.8×10 15

{ = hν}=hν { 3.31 eV = 6.62×10^{-34} ν}3.31eV=6.62×10 −34 ν { ν = 0.8 × 10^{15} Hz}ν=0.8×10 15 Hz

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