The frequency of a photon associated with an
energy of 3.31 eV is(given h = 6.62 x 10-34 Js)
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Answer:
{ = hν}=hν
{ = hν}=hν { 3.31 eV = 6.62×10^{-34} ν}3.31eV=6.62×10
{ = hν}=hν { 3.31 eV = 6.62×10^{-34} ν}3.31eV=6.62×10 −34
{ = hν}=hν { 3.31 eV = 6.62×10^{-34} ν}3.31eV=6.62×10 −34 ν
{ = hν}=hν { 3.31 eV = 6.62×10^{-34} ν}3.31eV=6.62×10 −34 ν { ν = 0.8 × 10^{15} Hz}ν=0.8×10
{ = hν}=hν { 3.31 eV = 6.62×10^{-34} ν}3.31eV=6.62×10 −34 ν { ν = 0.8 × 10^{15} Hz}ν=0.8×10 15
{ = hν}=hν { 3.31 eV = 6.62×10^{-34} ν}3.31eV=6.62×10 −34 ν { ν = 0.8 × 10^{15} Hz}ν=0.8×10 15 Hz
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