The frequency of a sound source is 540Hz. The number of times the source vibrates in a minute is
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1
Hey Mate here is your answer......
This answer is verified ✅✅
![formula \: of \: time \: period \: = \frac{1}{f} formula \: of \: time \: period \: = \frac{1}{f}](https://tex.z-dn.net/?f=formula+%5C%3A+of+%5C%3A+time+%5C%3A+period+%5C%3A++%3D++%5Cfrac%7B1%7D%7Bf%7D+)
Given,
Frequency, f = 540Hz
put in formula.........
![time \: period \: = \frac{1}{540} s \\ time \: period \: = 0.00185185s time \: period \: = \frac{1}{540} s \\ time \: period \: = 0.00185185s](https://tex.z-dn.net/?f=time+%5C%3A+period+%5C%3A++%3D++%5Cfrac%7B1%7D%7B540%7D+s+%5C%5C+time+%5C%3A+period+%5C%3A++%3D+0.00185185s)
The source vibrate in minute....
minute = 0.00185185 × 60m
minute = 0.111111 m
![hope \: it \: will \: help \: u \: and \: plzz \: mark \: my \: answer \: as \: a \: brainliest.... hope \: it \: will \: help \: u \: and \: plzz \: mark \: my \: answer \: as \: a \: brainliest....](https://tex.z-dn.net/?f=hope+%5C%3A+it+%5C%3A+will+%5C%3A+help+%5C%3A+u+%5C%3A+and+%5C%3A+plzz+%5C%3A+mark+%5C%3A+my+%5C%3A+answer+%5C%3A+as+%5C%3A+a+%5C%3A+brainliest....)
This answer is verified ✅✅
Given,
Frequency, f = 540Hz
put in formula.........
The source vibrate in minute....
minute = 0.00185185 × 60m
minute = 0.111111 m
Answered by
13
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Frequency is defined as the number of oscillations per second. It is given by the relation:
Frequency = Number of Oscillations / Total Time
Number of oscillations = Frequency × Total time
Given, Frequency of sound = 540 Hz
Total time = 1 min = 60 s
Number of oscillations/Vibrations = 540 × 60 = 32400
Hence, the source vibrates 32400 times in a minute, producing a frequency of 540 Hz.
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