Question

The frequency of a tuning fork is 160 Hz. What is its time period?​

Answer 1

Answer:

$Given:$

$Frequency (f) = 160 Hz$

$Time \: period \: (T) = \frac{1}{f}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 0.00625 \: sec$

$\therefore{The \: time \: period \: is \: 0.00625 \: sec.}$