Question

The frequency of a tunning fork is 384 Hz . Find its time period .

Answer 1

hey.
your solution is.
frequency=1/time period.
i.e n=1/T.
.°. T= 1/n.
T=1/384.
T=.0026 s

Answer 2

Given :

Frequency of tunning fork , f = 384 Hz .

To Find :

The time period of tunning fork .

Solution :

We know , time period is given by :

$T=\dfrac{1}{f}\\\\T=\dfrac{1}{384}\ s\\\\T=2.6\times 10^{-3}\ s$

Therefore , the time period of tunning fork is $2.6\times 10^{-3}\ s$ .

Hence , this is the required solution .

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