Question

the frequency of a wave propagating in a string is 20 hertz what will be the difference in the phase
of a particle of the string of time interval 0.01 second​

Answer 1

Explanation:

Answer is given in the attachment

Answer 2

The phase difference is 0.4 π.

Explanation:

Given that,

Frequency = 20 Hertz

Time interval = 0.01 sec

Let x be path difference.

Using formula of distance

$d=vt$

Where, v = velocity

t = time

d = distance

Put the value into the formula

$x=vt$

Using formula of wavelength

$\lambda=\dfrac{v}{f}$

Where, v = velocity

f = frequency

We need to calculate the phase difference

Using formula of path difference

$x=\dfrac{\lambda\times\phi}{2\pi}$

$\phi=\dfrac{2\pi\times v\times t\times f}{v}$

$\phi=2\pi\times20\times0.01$

$\phi=0.4\pi$

Hence, The phase difference is 0.4 π.

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Topic : phase difference

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