The frequency of an autosomal recessive Allele is 0.4. Then what will be the frequency of heterozygotes in progeny among 4000 individual ?
(1) 2000 (2) 1920 (3) 2400 (A) 1600
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The frequency of the recessive allele is q=0.4 (given)
Hence, p=1−0,4=0.6 (as p = 1- q)
According to Hardy- Weinberg principle, p
2
+ 2pq + q
2
=1
hence, p
2
=(0.6)
2
=0.36
q
2
=(0.4)
2
=0.16
2pq=0.48
since, 2pq is the frequency of hetrozygous carrier,
= 0.48×200
= 96 Individuals
So, the correct answer is
′
96
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