The frequency of cells in a population that are undergoing mitosis (the mitotic index) is a convenient way to estimate the length of the cell cycle. In order to measure the cell cycle in the liver of the adult mouse by measuring the mitotic index, liver slices are prepared and stained to easily identify cells undergoing mitosis. It was observed that only 3 out of 25,000 cells are found to be undergoing mitosis. Assuming that m phase lasts 30 minutes, calculate the approximate length of the cell cycle in the liver of an adult mouse?
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ANSWER: 42 HOURS
Explanation:
mitotic index I = (P+M+A+T)/ TOTAL cell, N) *100 %
(P+M+A+T) — the sum of all cells in phase as prophase, metaphase, anaphase and telophase, respectively; N — total number of cells.
Mitototic index (MI) is 3/25000 x 100 = 1.2 %
From the cell cycle, 1.2% is mitotic and the rest will obviously be interphase.
So, 1.2% is 30 minutes, so 100% (length of total cell cyle) is 2500 minutes (42hours)
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