The frequency of particle performing circular motion changes from 10 r.p.m to 30 r.p.m in 20 sec. find angular acceleration
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Answered by
12
Answer:
0.6284
Explanation:
Initial angular velocity ω
0
=60×
60sec
2π
=2π
Final angular velocity ω
t
=130×
60sec
2π
=6π
As we know ω
t
=ω
0
+αt
⇒α=
t
ω
t
−ω
0
=
20
6π−2π
=0.6284rad/s
2
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