Chemistry, asked by nidhi1014, 11 months ago

The frequency of radiation emitted when th
electron falls from n = 4 to n = 1 in a hydroge
atom will be (Given ionization energy
H = 2.18 x 10-18 J atom' and h = 6.625 x 10-34 Je​

Answers

Answered by AwesomeSoul47
6

Answer:

plz mark as brainlist plz it's helpful for me

The frequency of radiation emitted when an electron falls from n=4 to n=1 in a H atom will be ( Given that: ionisation energy of H atom : 2.18 x 10^ -18 J/atom and Planck's constant = 6.625 x 10^ -34 J/s). : a) 1.03 x 10^15 per second

Answered by Rohitpoul
7

Answer:

if this is the answer then plz follw me and like it

Attachments:
Similar questions