Question

The frequency of rotation of a spinning top is 10hz if it is brought to rest in 6.28s find the an
gular accelaration of a particle on its surface

Answer 1

Answer:

Angular acceleration = 10 rad/s^2

Explanation:

hope it is helpful

Answer 2

Answer:

Given:-

frequency=10hz,time=6.28sec

Formula:-

angular velocity = 2πf

= 2×22/7×10

= 440/7

= 62.85 rad/sec

angular acceleration = angular velocity/time

=62.85/6.28

= 10 rad/sec²

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