The frequency of the class 800 -1000 is 22. The value of fixi for this class is *
Answers
Step-by-step explanation:
800 -1000 then xi = (800+1000)/2 = 900
therefore fi xi = 22 × 900 = 19800
Answer:
the value of fixi for the class interval (800-1000) with a frequency of 22 is 19800.
Step-by-step explanation:
- In statistics, fixi represents the product of the frequency of a class "fi" and the midpoint of the class interval "xi".
- To find the value of fixi for the class interval (800-1000 )with a frequency of 22, we need to first find the midpoint of the interval.
Midpoint of the interval = (lower limit + upper limit) / 2
= (800 + 1000) / 2
= 900
Now we can use the formula for fixi:
fixi = fi * xi
where fi is the frequency and xi is the midpoint of the class interval.
Substituting the values we have:
fixi = 22 * 900
fixi = 19800
Therefore, the value of fixi for the class interval 800-1000 with a frequency of 22 is 19800.
In statistics, a class interval is a range of values that are grouped together into a single category or class. Class intervals are often used to represent large sets of data in a more manageable way, and they are commonly used in constructing histograms, frequency tables, and other graphical representations of data.
To learn more about frequency tables from the link below
https://brainly.in/question/55285228
To learn more about class interval from the link below
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