Math, asked by kirankshirsagar1801, 8 months ago

The frequency of the class 800 -1000 is 22. The value of fixi for this class is *



Answers

Answered by biligiri
9

Step-by-step explanation:

800 -1000 then xi = (800+1000)/2 = 900

therefore fi xi = 22 × 900 = 19800

Answered by chandujnv002
0

Answer:

the value of fixi for the class interval (800-1000) with a frequency of 22 is 19800.

Step-by-step explanation:

  • In statistics, fixi represents the product of the frequency of a class "fi" and the midpoint of the class interval "xi".
  • To find the value of fixi for the class interval (800-1000 )with a frequency of 22, we need to first find the midpoint of the interval.

Midpoint of the interval = (lower limit + upper limit) / 2

= (800 + 1000) / 2

= 900

Now we can use the formula for fixi:

fixi = fi * xi

where fi is the frequency and xi is the midpoint of the class interval.

Substituting the values we have:

fixi = 22 * 900

fixi = 19800

Therefore, the value of fixi for the class interval 800-1000 with a frequency of 22 is 19800.

In statistics, a class interval is a range of values that are grouped together into a single category or class. Class intervals are often used to represent large sets of data in a more manageable way, and they are commonly used in constructing histograms, frequency tables, and other graphical representations of data.

To learn more about frequency tables from the link below

https://brainly.in/question/55285228

To learn more about class interval from the link below

https://brainly.in/question/1965606

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