The frequency of the light emitted by the source of light on the rocket as observed by the
person on the rocket is 6x10" Hz. If the speed of the rocket is 0.36c, then determine the
wavelength of the light as observed by a person on Earth.
Answers
Answer:
Wave length= Speed/frequency
=0.36/(6x10)
=1 798.75475 kilometers
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Therefore the wavelength of the light as observed by a person on Earth is 0.18 × 10⁻³ m.
Given:
The frequency of the light = 6x10¹¹ Hz
The speed of the rocket = 0.36c
To Find:
The wavelength of light is observed by a person on Earth.
Solution:
The given question can be solved as shown below.
Given that,
The frequency of the light = 6x10¹¹ Hz
The speed of the rocket = 0.36c
⇒ ( Frequency ) × ( Wavelength ) = Speed
⇒ ( 6x10¹¹ ) × λ = ( 0.36c )
⇒ ( 6x10¹¹ ) × λ = 0.36 × 3 × 10⁸ [ ∵ Speed of light = c = 3 × 10⁸ m/s ]
⇒ λ = ( 0.36 × 3 × 10⁸ ) / ( 6x10¹¹ ) = 0.36 / ( 2 × 10³ )
⇒ λ = 0.18 × 10⁻³
Therefore the wavelength of the light as observed by a person on Earth is 0.18 × 10⁻³ m.
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