Physics, asked by kireetiinkoolu2002, 11 months ago

The frequency of the particle in SHM is 12Hz. It's amplitude is 4 cm. It's initial displacement is 2cm towards positive extreme position. The equation for the displacement is....

Answers

Answered by banwadikaraayush
20

f=12Hz

w=2πf=24π rad/sec

A=4cm;x=2cm

x=Asinϕ

2=4sinϕ

Thus ϕ=π6

Thus

x=0.04sin(24πt+π6)


Answered by Safiyakhanum
8

Refer this attachment mate......... Hope it helps u

Attachments:
Similar questions