Question

The frequency of the whistle of an engin is 600 hertz is moving with a speed of 30 metre per second inverse towards a stationary observer the apparent frequency is?
(speed of sound 330ms1)

Answer 1

Answer:

660 HERTZ

Explanation:

★ DOPPLER EFFECT

«★» OBSERVER ----> STATIONARY

GIVEN ;

★ Frequency ( n ) :- 600 Hz

★ Speed of Engine ( Vs ) :- 30 m / s

★ Speed of Engine ( Vs ) :- 30 m / s { s ≈ Source }

★ Speed of Sound ( V ) :- 330 m/s

★ Apparent Frequency ( nx ) = ???

Now ;

♠______BY USING FORMULA_________♥

★ ::WHEN OBSERVER MOVING TOWARDS STATIONARY OBSERVER ::★

$n {x} \: = n \: ( \: \frac{v}{v \: - vs} )$

» nx = 600 [ 330 / { 330 - 30 } ]

» nx = 600 [ 330 / 300 ]

» nx = 2 [ 330 ]

«★→» nx = 660 Hz

ANSWER :- HENCE ;

when source is moving with 30 m/s ; APPARENT FREQUENCY heard BY OBSERVER IS

660 HERTZ .

★★★_______WAVE MOTION_______★★★