Question

The frequency of tuning fork is 500Hz and the velocity of sound in air 340ms.

How far does sound travel when the fork executes 50 vibrations?

(ɴᴇᴇᴅ ϙᴜᴀʟɪᴛʏ ᴀɴsᴡᴇʀ)​

Answer 1

Answer:

34 metres is the required answer .

Explanation:

According to the Question

It is given that ,

• Frequency ,f = 500Hz
• Speed of sound ,s = 340m/s
• No. of vibration ,n = 50

we need to calculate the distance travelled by the sound .

Firstly we calculate the time period of 500Hz frequency.

• t = 1/f

where,

t denote time period

f denote frequency

Substitute the value we get

➻ t = 50/500

➻ t = 10/100

➻ t = 1/10

➻ t = 0.1 s

Now, calculating the the distance covered by sound when the fork executes 50 vibrations.

As we know that distance covered is calculated by the product of speed and time taken .

• D = s × t

substitute the value we get

➻ D = 340 × 0.1

➻ D = 34 m

• Hence, the distance covered by the sound when fork executes 50 vibrations will be 34 metres.

Answer 2

Question:

• The frequency of tuning fork is 500 Hz and the velocity of sound in air 340 m/s. How far does sound travel when the fork executes 50 vibrations?

Answer:

• Distance travelled by sound when tunning fork executes 50 vibrations is 34 meters.

Explanation:

Given that:

• Frequency of tunning fork = 500 Hz
• Velocity of sound in air = 340 m/s
• Number of vibrations = 50

To Find:

• Distance travelled by the sound?

Solution:

• Here, firstly we will calculate time period of 500 Hz frequency.

We know that,

⧪ $\boxed{\bf{\purple{Time\:period = \dfrac{1}{Frequency}}}}$ ⧪

According to the question by using the formula we get,

➼ $\sf Time\:period = \dfrac{5\cancel{0}}{50\cancel{0}}$

➼ $\sf Time\:period = {\cancel{\dfrac{5}{50}}}$

➼ $\bf\pink{Time\:period = \dfrac{1}{10}\:s}$

∴ Hence, time period of 500 Hz frequency is 1/10 seconds.

• Now, we have all required values. So, let's calculate the distance travelled by sound when tunning fork executes 50 vibrations, as it given by product of speed and time.

Again we know that,

⧪ $\boxed{\bf{\green{Distance = Speed\:\times\:Time}}}$ ⧪

According to the question by using the formula we get,

➼ $\sf Distance = 34\cancel{0}\:\times\:\dfrac{1}{1\cancel{0}}$

➼ $\sf Distance = 34\:\times\:1$

➼ $\bf\red{Distance = 34\:m}$

∴ Hence, distance travelled by sound when tunning fork executes 50 vibrations is 34 meters.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬