The friction between block B and the table is 200 N. Find the maximum possible mass of block A for which the system will be in equilibrium.
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The tension in wire T attached to the hook can be determined as,
Tsin(θ)w
T=
sin(θ)
w
The force due to static friction on block A is equal to the horizontal component of the
tension.
The expression for frictional force is,
F
f
=Tcos(θ)
Substitute T=
sin(θ)
w
in the frictional force expression
F
f
=
sin(θ)
w
cos(θ)
=wcot(θ)
Substitute 12 N for w and 45
∘
for θ.
F
f
=(12N)cot(45
∘
)
=12N
Therefore friction force exerted on block A is 12N.
do same like this
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