Question

The friction coefficient between the board and the floor shown in figure is µ. Find the maximum force that the man can exert on the rope so that the board does not slip on the floor.

Answer 1

Let the Tension in the String be T.

∴ T = (M + m)g - N

⇒ N = (M + m)g - T

Now, Friction = μN.

T =  μ((M + m)g - T)

[Since, On maximum can became equal to T only, otherwise it will be less than it always.]

∴ T (1 + μ) = (M + m)μg

T = μg(M + m)/(1 + μ)

Hope it helps.

Answer 2

Answer:

this is the ans.. hope it helped you ✌✌