Question

The frictional force acting on 1 kg block is

Answer 1

Answer:

The frictional force acting on 1 kg block is 0.01

Explanation:

On smooth surface acceleration of both blocks when it moves will be ,

$\mathrm{a}=10 / 100+1 \mathrm{m} / \mathrm{s}^{2}$

For this acceleration required frictional force will be, if mass of block is 1 kg

F = ma = 1 x 10/101 N = 10/101N

Maximum static friction will be, μ x mg = 0.5 x 10 = 5N > f  

F = 10/101 N = 0.01 (Approx)