Question

The frictional force acting on a 0.5 kg object and a floor is 3 N. What is the coefficient of friction between the object and the floor?

Answer 1

Given :

▪ Mass of object = 0.5kg

▪ Magnitude of frictional force = 3N

To Find :

▪ Co-efficient of friction b/w the object and the floor.

Formula :

➡ For a body placed on horizontal surface, N = mg

$\bigstar\:\underline{\boxed{\bf{\red{f=\mu\times N=\mu \times (mg)}}}}$

• f denotes frictional force
• u denotes co-efficient of friction
• N denotes normal reaction

Calculation :

$\dashrightarrow\sf\:f=\mu\times (mg)\\ \\ \dashrightarrow\sf\:3=\mu\times (0.5\times 10)\\ \\ \dashrightarrow\sf\:3=5\mu\\ \\ \dashrightarrow\sf\:\mu=\dfrac{3}{5}\\ \\ \dashrightarrow\underline{\boxed{\bf{\orange{\mu=0.6}}}}\:\gray{\bigstar}$

Answer 2

Given that:

• Frictional force acting on a 0.5 kg object and floor is 3 N.

To Find:

• Coefficient of friction between object and the floor.

Formula Used:

• F = μN

where,

F is frictional force

μ is coefficient of Friction

N is the normal reaction

SOLUTION:

Let the coefficient of Friction be μ.

So, Using the above formula, we have

3 = μ*0.5*10

μ = 3/5 = 0.6

So, coefficient of friction is 0.6.

Hope this helps