the frictional force of air on a body of mass 0.25 kg falling with acceleration 9.2 is
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Answer:
0.15 N
Explanation:
Given the frictional force of air on a body of mass 0.25 kg falling with acceleration 9.2 is
Acceleration due to gravity is 9.8 m/s^2. Now acceleration due to frictional force of a falling body is reduced to 9.2 m/s^2
So change in acceleration will be 9.8 – 9.2 = 0.6 m/s^2
Now friction due to air will be equal to m x a
= 0.25 x 0.6
= 0.15 N
So Frictional force on body due to air is 0.15 N
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