Question

the frictional force of the air on a body of mass 0.25 kg falling with an acceleration of 9.2 m/s^2 will be

Answer 1

Acceleration due to gravity = 9.8 m/s^2

Due to frictional force of air, acceleration of falling body is reduced to 9.2m/s^2

Change in acceleration due to friction= 9.8 - 9.2 =0.6m/s^2

Friction due to air = ma = 0.25×0.6 = 0.15N

Frictional force on body due to air is 0.15 N

Answer 2

Answer:

0.15N

Explanation:

change in acceleration due to frictional force= 9.8-9.2=0.6m/s^2

friction force of air on body = ma

=0.25*0.6 = 0.15N

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