Question

the frist and last terms of an AP are 17 and 350 respectively if the common difference is 9 how many terms are their what are their sum​

Answer 1

Step-by-step explanation:

i hope these answer / solution is useful for you

Answer 2

Step-by-step explanation:

a=t1=17 , tn=350 and d=9

tn= a+(n-1)d

350=17+(n-1)9

350=17+9n-9

350=8+9n

350-8=9n

342=9n

342/9=n

38=n

Sn=S38=?

Sn=n/2[2a+(n-1)d)]

S38=38/2[34+(38-1)9]

S38=19(34+37*9)

S38=19*367

S38=6873