Math, asked by parmarsaarthak, 2 months ago

the
from wha
and Jyoti are in charge of ma
banner for the basketball game
need for a square shaped banner
many sheets of poster paper will
side 4 mit each poster paper has lens
cm and breadth 20 cm?​

Answers

Answered by brunda12gmailcom
0

Let the paper size be x inches in length and y inches in width.

the length of the printed space would be x-8 inches and width would be y-4 inches. Print area would thus be (x-8)(y-4)= 50.

From this

y

=

4

+

50

x

8

=

4

x

+

18

x

8

.

Also from the same equation on simplifying, it is xy-8y-4x+32=50.

Since the area of the paper of size x inches by y inches is xy, let it be denoted as A. Thus

A-8y-4x=18 Or A= 8y+4x+18

A

=

32

x

+

144

x

8

+

4

x

+

18

. For minimum paper size

d

A

d

x

must be =0, hence,

d

A

d

x

=

32

(

x

8

)

(

32

x

+

144

)

(

x

8

)

2

+

4

=

0

400

(

x

8

)

2

+

4

=

0

(

x

8

)

2

=

100

x-8=10

x=18, hence y=

4

+

50

x

8

=9

Dimension of minimum paper size would be 18 inches by 9 inches.

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