the
from wha
and Jyoti are in charge of ma
banner for the basketball game
need for a square shaped banner
many sheets of poster paper will
side 4 mit each poster paper has lens
cm and breadth 20 cm?
Answers
Answered by
0
Let the paper size be x inches in length and y inches in width.
the length of the printed space would be x-8 inches and width would be y-4 inches. Print area would thus be (x-8)(y-4)= 50.
From this
y
=
4
+
50
x
−
8
=
4
x
+
18
x
−
8
.
Also from the same equation on simplifying, it is xy-8y-4x+32=50.
Since the area of the paper of size x inches by y inches is xy, let it be denoted as A. Thus
A-8y-4x=18 Or A= 8y+4x+18
A
=
32
x
+
144
x
−
8
+
4
x
+
18
. For minimum paper size
d
A
d
x
must be =0, hence,
d
A
d
x
=
32
(
x
−
8
)
−
(
32
x
+
144
)
(
x
−
8
)
2
+
4
=
0
−
400
(
x
−
8
)
2
+
4
=
0
(
x
−
8
)
2
=
100
x-8=10
x=18, hence y=
4
+
50
x
−
8
=9
Dimension of minimum paper size would be 18 inches by 9 inches.
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