the front face of the top of a hurtbis triangular in shape. if AD: DB=3:2, Then AE:EC=
a) 2:3
b) 3:2
c) 2:5
d) 3:5
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Given : DE || BC
AD: DB=3:2
To Find : AE:EC
a) 2:3
b) 3:2
c) 2:5
d) 3:5
Solution:
if a line is drawn parallel to one side of a triangle intersecting the other two sides, then it divides the two sides in the same ratio.
DE || BC
=> AD/ DB = AE / EC
AD: DB=3:2 => AD/ DB = 3/2
=> 3/2 = AE/EC
=> AE / EC = 3/2
=> AE : EC = 3 : 2
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