Question

the frontage of a church is in the form of a rectangle with a triangle on top of it which is isosceles if the rectangular portion is of height 4 m the base of the triangle portion is 5 M and the height of the triangle is 2 metre find his total frontage area ? If this area of RS 20 per square metre what is the cost involved

Answer 1

Step-by-step explanation:

area of rectangle is

$5 \times 4 = 20 { m}^{2}$

are of triangle is

$\frac{1}{2} b h = \frac{1}{2} \times 2 \times 5 \\ \: \: \: \: \: \: \: \: \: =5 {m}^{2}$

thus area of the figure is 25m square

cost is 25×20=500rs.

it's quite cheap... I must say

Answer 2

Answer:

area of rectangle is

5 \times 4 = 20 { m}^{2}5×4=20m2

are of triangle is

\begin{gathered}\frac{1}{2} b h = \frac{1}{2} \times 2 \times 5 \\ \: \: \: \: \: \: \: \: \: =5 {m}^{2}\end{gathered}21bh=21×2×5=5m2

thus area of the figure is 25m square

cost is 25×20=500rs.