the frustum of a right circular cone has height 12cm radius of base 8cms and raduis of top 3cms then the ration of the volume of the frustum and its total surface area
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97:54
Step-by-step explanation:
πh/3 *(R^2+r^2 + Rr) : (πRl + πrl+ πR^2 + πr^2)
=h/3 *(R^2 + r^2 + Rr) : [l(R + r) + R^2 +r^2]
[ note :- slant height of conical frustum
l =√[ h^2 + (R-r)^2] = √(12^2+(8-3)^2] = 13 cm]
= 12/3 *(64+9+24) : [13(8+3)+64+9]
= 388 : 216 = 97 : 54
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