Question

The full deflection current of moving coil Galvanometer is 1 mA. If it is converted into an ammeter of 10 A range then value of shunt is
[Resistance of Galvanometer = 1 kohm]​

Answer 1

Answer:

Given: A galvanometer of 100 resistance gives full scale deflection with 0.01A current

To find the resistance that should be connected convert it into an ammeter of range 10A

Solution:

Galvanometer is a very sensitive instrument therefore it cannot measure heavy currents. In order to convert a Galvanometer into an Ammeter, a very low shunt resistance is connected in parallel to Galvanometer. Value of shunt is so adjusted that most of the current passes through the shunt.

If resistance of galvanometer is R

g

and it gives full-scale deflection when current I

g

is passed through it. Then,

V=I

g

R

g

⟹V=0.01A×100Ω

⟹V=1V

Let a shunt of resistance (R

s

) is connected in parallel to galvanometer. If total current through the circuit is I.

I=10A=I

(10−0.01)R

s

=100×0.01

⟹R

s

=0.1Ω

is the resistance that should be connected in parallel to convert it into an ammeter of range 10A

Answer 2

Answer:

A shunt resistor of 5.01 mohm should be connected in parallel with the galvanometer to convert it into an ammeter of 10 A range.

Explanation:

To convert a galvanometer into an ammeter, we need to connect a shunt resistor in parallel with the galvanometer. The value of the shunt resistor can be calculated using the formula:

Ig = Im + Ish

where,

Ig = full-scale deflection current of the ammeter

Im = maximum current that can be measured by the ammeter

Ish = current flowing through the shunt resistor

In this case, we want to convert the galvanometer into an ammeter of 10 A range. So, the maximum current that can be measured by the ammeter is 10 A.

Since the full deflection current of the galvanometer is 1 mA, we can assume that the sensitivity of the galvanometer is 1 mA/division. Therefore, to get a full-scale deflection of 10 divisions (i.e., for a range of 10 A), we need a current of 10 mA (i.e., 10 divisions x 1 mA/division) to flow through the galvanometer.

Now, we can use the formula above to calculate the value of the shunt resistor:

Ish = Ig - Im

Ish = 10 mA - 10 A

Ish = -9.99 A (since the shunt is in parallel, its current is opposite in direction to the ammeter's current)

We need to find the value of the shunt resistor that will allow a current of -9.99 A to flow through it. Since the galvanometer has a resistance of 1 kohm, we can use Ohm's law to calculate the resistance of the shunt:

Ish = Vshunt / Rshunt

-9.99 A = Vshunt / Rshunt

Assuming a nominal voltage drop of 50 mV across the shunt resistor (which is common for a 10 A ammeter), we can calculate the resistance of the shunt:

Rshunt = Vshunt / Ish

Rshunt = 50 mV / -9.99 A

Rshunt = 5.01 mohm

Therefore, a shunt resistor of 5.01 mohm should be connected in parallel with the galvanometer to convert it into an ammeter of 10 A range.

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