The full marks for a paper is 300. The break-up of the
marks into theory (X), practical (Y) and (Z) project, which
are the three components of evalution is 6 : 5 : 4. In order to
pass one has to score at least 40%, 50% and 50%
respectively in XYZ and 60% in aggregate. The marks
scored by four students ABC and D are shown in the given
Bar Graph.
Answers
Student C has scored 30% more marks in practical than student B.
Step-by-step explanation:
The full marks for a paper is 300.
The break-up of the marks into theory (x), Practical (y) and Project (z).
We can see the marks of B and C by observing the given bar graph and the marks are as given below :
Student Theory (x) Practical (y) Project (z)
A 60 70 50
B 50 50 30
C 70 80 60
D 80 70 30
We will find how much percentage marks than B has C scored in practical.
Student B scored in practical = 50%
Student C scored in practical = 80%
Difference = 80% - 50% = 30%
Student C has scored 30% more marks in practical than student B.
Learn more about bar graph : https://brainly.in/question/2564555