Physics, asked by kakaji95, 10 months ago

The full scale deflection current of a galvanometer of resistance 1 ohm is 5 mA. To measure the potential difference of 5 V, the resistance connected to the galvanometer is

Answers

Answered by chandu987

1

Answer:

dear please mention in terms of what u need answer

Answered by Gracy999

1

Answer:

Explanation:

Ig(R + Rg)= V

R= (5/5×10^-3) -1

= 10^3- 1

=0.999*10^3

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