Question

the function defined by v(x)=3.8x converts a volume of x gallons into v(x) liters

find an equation defining y=v^-1(x)​

Answer 1

SOLUTION

GIVEN

A function defined by v(x) = 3.8x

converts a volume of x gallons into v(x) litres

TO DETERMINE

The equation defining

$\sf{ y = {v}^{ - 1} (x)\: }$

EVALUATION

Here a function defined by v(x) = 3.8x

function defined by v(x) = 3.8x converts a volume of x gallons into v(x) litres

Now

$\sf{ y = {v}^{ - 1} (x)\: }$

$\implies \sf{v(y) = x\: }$

$\implies \sf{3.8y = x\: }$

$\displaystyle \implies \sf{y= \frac{x}{3.8} \: }$

$\displaystyle \implies \sf{y= {v}^{ - 1} (x) = \frac{x}{3.8} \: }$

FINAL ANSWER

$\boxed{\displaystyle \sf{ \: \: y= {v}^{ - 1} (x) = \frac{x}{3.8} \: } \: }$

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LEARN MORE FROM BRAINLY

Let A={(x,y):x,y€z,x²+y²≤16}, then

the number of reflexive relations on set A

a)2^49 b)2^2401 c)2^2352 d)2^1176

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