Math, asked by yhaexb, 6 months ago

the function f is defined on the real numbers by f(x)=2+x-x2, what is the value of f(2)

Answers

Answered by ajitsarma61
0

Answer:

f (x)=2+x-x^2

f (2)=2+2-2^2

=4-4

=0

Answered by vrao99060
0

Answer:

0

Step-by-step explanation:

if

2=2+2-2^

then X=2+x-x^

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