the function f is defined on the real numbers by f(x)=2+x-x2, what is the value of f(2)
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Answered by
0
Answer:
f (x)=2+x-x^2
f (2)=2+2-2^2
=4-4
=0
Answered by
0
Answer:
0
Step-by-step explanation:
if
2=2+2-2^
then X=2+x-x^
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