The function f
is defined on the set
of integrers and satisfy
4 n 711000
fin) = {
n-3
n<1000
(fents) of
then find f (84)
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Answer:
Let us assume: f(1)=x.
Then, f(2)=f(2/2)=f(1)=x
f(3)=f(3+5)=f(8)=f(8/2)=f(4/2)=f(2/1)=f(1)=x.
Similarly, f(4)=x
f(5)=f(5+5)=f(10/2)=f(5)=y.
So, it will have two values. All multiples of 5 will have value y and others will have value x.
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