Question

the function f(x) = p(x-q)(x-r) passes through the points (-2,0), (0,-4), (4,0)

whats q,r,p

and axis of sym?

Answer 1

Answer:

1/2, -2, 4

Step-by-step explanation:

Since value of function at x = -2 and 4 is 0, they are the roots of the quadratic.

So q and r are -2 and 4. Also put in the value of the point (0,-4).

$(-4)=p(2)(-4)\\p=\frac{1}{2}$