Question

The function f(x)=x2-3x + 7 has a

critical point at​

Answer 1

SOLUTION

TO DETERMINE

The function f(x) = x² - 3x + 7 has a critical point at

EVALUATION

Here the given function is

f(x) = x² - 3x + 7

Differentiating both sides with respect to x we get

f'(x) = 2x - 3

For critical points we have

f'(x) = 0

⇒ 2x - 3 = 0

⇒ 2x = 3

⇒ x = 3/2

FINAL ANSWER

The function f(x) = x² - 3x + 7 has a critical point at x = 3/2

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