Question

The function f(x) = x2 − 6x + 3 is transformed such that g(x) = f(x − 2). Find the vertex of g(x).

Answer 1

Answer:

Given that,f(x)=x^2-6x+3

or,g(x)=f(x-2)=(x-2)^2-6*(x-2)+3

or,g(x)=x^2-2*x*2+(2)^2-6x+12+3

or,g(x)=x^2-4x+4-6x+12+3

Hence,g(x)=x^2-10x+19